Question

What is the molarity of a solution that contains 98 g of H2SO4 in 0.05 L of solution?

Answer 1

Answer

20 mol/L

Explanation

Given:

Mass of H₂SO₄ = 98 g

Volume = 0.05 L

From the Periodic Table; Atomic mass (H = 1.0 g, O = 16.0 g, S = 32.0 g)

What to find:

Molarity of the solution.

Step-by-step solution

Step 1: Convert the given mass of 98 g to mole.

The formula to determine the mole is given by:

$\text{mole }=\frac{Mass}{Molar\text{ mass}}$

Molar mass of H₂SO₄ = (2 x 1.0 g) + 32.0 g + (4 x 16.0 g) = 98 g/mol

So mole is

$\text{Mole }=\frac{98\text{ g}}{98\text{ g/mol}}=1.0\text{ mol}$

Step 2: Determine the molarity

The molarity formula is given by:

$\text{Molarity }=\frac{Mole}{Volume\text{ in L}}=\frac{1.0\text{ mol}}{0.05\text{ L}}=20\text{ mol/L}$