Answers:
(1) r = 0
(2) The equation has no solution
Explanations:
(1) Given the expression:
[tex]8(11+2r)=12(\frac{4}{3}r+\frac{22}{3})[/tex]Removing the brackets, we have:
[tex]88+16r=\frac{48}{3}r+\frac{264}{3}[/tex]Multiply both sides by 3
[tex]\begin{gathered} 264-48r=48r+264 \\ \end{gathered}[/tex]Collect like terms
[tex]\begin{gathered} 48r+48r=264-264 \\ 48r=0 \end{gathered}[/tex]Divide both sides by 48
[tex]r=\frac{0}{48}=0[/tex](2) Given the expression:
[tex]-8(10+7k)+8k=9+4(6-12k)[/tex]Remove brackets
[tex]-80-56k+8k=9+24-48k[/tex]Collect like terms
[tex]\begin{gathered} -56k+8k+48k=9+24+80 \\ \end{gathered}[/tex]Simplifying this, the variable k vanishes, leaving us with nothing to find. Therefore, the equation has no solution.