Question

Sodium reacts with oxygen to produce sodium oxide.4Na(s)+O2(g)→2Na2O(s)If you have 16.0 g of Na , how many grams of O2 are required for the reaction?

Answer 1

Answer:

5.57 grams

Explanations:

Given the reaction between sodium and oxygen expressed as:

$4Na(s)+O_2(g)\rightarrow2Na_2O(s)$

Given the following parameters

Mass of sodium = 16.0g

Determine the moles of sodium

$\begin{gathered} moles\text{ of Na}=\frac{mass}{molar\text{ mass}} \\ moles\text{ of Na}=\frac{16}{23} \\ moles\text{ of Na}=0.6957moles \end{gathered}$

According to stoichiometry, 4 moles of sodium reacts with 1 mole of oxygen, the moles of oxygen that reacted is given as;

$\begin{gathered} moles\text{ of O}_2=\frac{0.6957}{4} \\ moles\text{ of O}_2=0.1739moles \end{gathered}$

Determine the mass of oxygen that reacted

$\begin{gathered} mass\text{ of O}_2=mole\times molar\text{ mass} \\ mass\text{ of O}_2=0.1739\times32 \\ mass\text{ of O}_2=5.57grams \end{gathered}$

Hence the mass of oxygen that reacted is 5.57 grams