Given:
SR = 26 m.
To find:
The area of shaded region.
Solution:
Here, QR ~ PS. So, angle PTS = angle QTR.
So, angle PTS = 73 degrees.
To find the area of the shaded region, we have to subtract the area of unshaded region from the area of the circle.
Here, SR is the diameter and SR = 26. So, the radius of the circle is 13 m.
Since, the unshaded regions are similar to each other. So, the total area of the unshaded region is:
[tex]\begin{gathered} A=2\times\frac{73}{360}\times\frac{22}{7}\times(13)^2 \\ =\frac{542828}{2520} \\ =215.41m^2 \end{gathered}[/tex]
The area of the circle is:
[tex]\begin{gathered} A=\pi r^2 \\ =\frac{22}{7}\times(13)^2 \\ =\frac{3718}{7} \\ =531.14 \end{gathered}[/tex]
So, the area of shaded region is:
[tex]531.14-215.41=315.73m^2[/tex]
Thus, the area of the shaded region is 315.73 m^2.
