Question

Find the value of the expression. 07-2 . (131 alw The value is I I

Answer 1

$\begin{gathered} \lbrack(\frac{3}{5})^0\rbrack^{-2} \\ (\frac{3}{5})^0=0.6^0=1 \\ \Rightarrow1^{-2}=\frac{1}{1^2}=\frac{1}{1}=1 \\ \Rightarrow\lbrack(\frac{3}{5})^0\rbrack^{-2}=1 \end{gathered}$