What is the value of sin E?Give your answer as a simplified fraction.

For this problem we first use the pythagorean theorem to find QH
[tex]\begin{gathered} QH^2+HE^2=QE^2 \\ QH^2=QE^2-HE^2=101^2-99^2=400 \\ QH=20 \end{gathered}[/tex]Then
[tex]\sin (E)\text{ =}\frac{QH}{QE}=\frac{20}{101}[/tex]