Question

Help with Algebra 2 question.14) An angle is in standard position and is terminal side pauses through point (-2,5), find sec.

Answer 1

Given:

An angle is in standard position and is terminal side passes through the point (-2,5),

Required:

To find the value of the secant function.

Explanation:

The value of the secant function is given as:

$sec\theta=\frac{r}{x}$

Where

$r=\sqrt{x^2+y^2}$

Consider x= -2 and y = 5

Now calculate the value of r by using the formula:

$\begin{gathered} r=\sqrt{(-2)^2+(5)^2} \\ r=\sqrt{4+25} \\ r=\sqrt{29} \end{gathered}$

Thus the required value is:

$sec\theta=\frac{\sqrt{29}}{-2}$

Final Answer:

$sec\theta=-\frac{\sqrt{29}}{2}$