Question

edAnswersweredQuestion 6How many H atoms are in 3.4 mol C21H23NO5?1.3 x 10³2.9 x 1042.0 x 10244.7 x 10254.7 x1025. This was the correct answer.↓0/1 pts0/1 ptc

Answer 1

Answer:

$atoms\text{ of H}=4.7\times10^{25}atoms$

Explanations:

Given the following parameters

moles of C21H23NO5 = 3.4 moles

Since there are 23 atoms of hydrogen in the compound, hence the moles of hydrogen in the compound is given as:

$\begin{gathered} moles\text{ of H}=23\times3.4 \\ moles\text{ of H}=78.2moles \end{gathered}$

According to the Avogadro's constant

$1mole\text{ of a substance}=6.02\times10^{23}atoms$

Convert the moles of hydrogen to atoms

$\begin{gathered} atoms\text{ of H}=78.2\times6.02\times10^{23} \\ atoms\text{ of H}=470.764\times10^{23} \\ atoms\text{ of H}=4.70764\times10^{25} \\ atoms\text{ of H}=4.7\times10^{25}atoms \end{gathered}$