Using the compound interest formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where:
A = Amount
P = Principal = $1821
r = Interest rate = 3% = 0.03
n = Number of times interest is compounded per year = 12
t = Time = 1
So:
[tex]\begin{gathered} A=1821(1+\frac{0.03}{12})^{12\cdot1} \\ A\approx1876.39 \end{gathered}[/tex]Answer:
$1876.39