You need to determine the measure of the arc BAD in the given circle P.
The angle measure of angle ∠BPD with the vertex in the center of the circle P is congruent to the measure of the intercepted arc BAD.
This means that to determine the measure of the arc, you need to determine the measure of the angle.
The measure of ∠BPD is equal to the sum of the measures of the adjacent angles that form it:
[tex]\angle\text{BPD}=\angle\text{BPA}+\angle\text{APE}+\angle\text{EPD}[/tex]∠APE and ∠EPD have an unknown measure but we know that they are equal, and we know that the total angle of a circle is 360º, i.e. the sum of all the angles is 360º
Let "x" represent the measure of angles ∠APE and ∠EPD, we can represent the total angle of the circle as follows:
[tex]360º=\angle\text{APE}+\angle\text{EPD}+\angle\text{DPC}+\angle\text{CPB}+\angle\text{BPA}[/tex]We know that
∠APE=∠EPD=x
∠DPC=42º
∠CPB=74º
∠BPA=136º
[tex]\begin{gathered} 360º=x+x+42+74+136 \\ 360=2x+252 \\ 360-252=2x \\ 2x=108 \\ \frac{2x}{2}=\frac{180}{2} \\ x=54º \end{gathered}[/tex]So ∠APE=∠EPD=54º
Now that we know the measure of these angles we can calculate the measure of ∠BPD
[tex]\begin{gathered} \angle\text{BPD}=\angle\text{BPA}+\angle\text{APE}+\angle\text{EPD} \\ \angle\text{BPD}=136+54+54 \\ \angle\text{BPD}=244º \end{gathered}[/tex]∠BPD=244º and, as mentioned before the measure of the intercepted arc is the same as the measure of the central angle, then its intercepted arc BAD = 244º as well.
