Question

In ABCD, the measure of ZD=90°, CB = 53, BD = 45, and DC = 28. What ratiorepresents the sine of ZB?|

Answer 1

SOLUTION

Step 1 :

In this question, we asked to find the value of

$\sin \text{ B}$$\begin{gathered} \text{where }\angle D=90^0 \\ BD\text{ = 45} \\ DC\text{ = 28} \\ BC\text{ = 53} \end{gathered}$

Step 2 :

We can are see clearly that 28 , 45, 53 ) iPythagoras' Triple, since:

$28^2+45^2=53^2$

Step 3 :

$\begin{gathered} \sin \text{ B = }\frac{28}{53} \\ =\text{ 0.5283} \end{gathered}$

CONCLUSION :

$\sin \text{ B = 0.5283}$