Question

Find the area of triangle ABC.A = 37.2°, b = 10.1 in., c = 6.2 in.A. 19 in²B. 20 in²C. 17 in²D. 18 in²

Answer 1

Given:

A = 37.2°

b = 10.1 in

c = 6.2 in

Let's find the area of the traingle.

To find the area, apply the formula below:

$\text{Area}=\frac{1}{2}\ast b\ast c\ast\sin A$

Hence, we have:

$Area=\frac{1}{2}\ast10.1\ast6.2\ast\sin 37.2$

Solving further:

$\begin{gathered} \text{Area}=\frac{1}{2}\ast10.1\ast6.2\ast0.605 \\ \\ \text{Area}=18.9\text{ }\approx19in^2 \end{gathered}$

Therefore, the area of triangle ABC is 19 square inches

ANSWER:

A. 19 in²