Question

Which of the following tables corresponds to the equation below?

Answer 1

Solution:

Given the equation;

$y=\frac{1}{4}(4^x)$

We would create a table of values such that x ranges from 0 to 5;

$\begin{gathered} x=0; \\ \\ y=\frac{1}{4}(4^0)=\frac{1}{4} \\ \\ (0,\frac{1}{4}) \\ \\ x=1; \\ \\ y=\frac{1}{4}(4^1)=1 \\ \\ (1,1) \\ \\ x=2; \\ \\ y=\frac{1}{4}(4^2)=4 \\ \\ (2,4) \end{gathered}$

Then;

$\begin{gathered} x=3; \\ \\ y=\frac{1}{4}(4^3)=16 \\ \\ (3,16) \\ \\ x=4; \\ \\ y=\frac{1}{4}(4^4)=64 \\ \\ (4,64) \\ \\ x=5; \\ \\ y=\frac{1}{4}(4^5)=256 \\ \\ (5,256) \end{gathered}$

Thus, the correct table is;