Question

Solve the system using the addition method 5x-2y=32x-y=0What is the y-valueA. 3B. 6C. -3D. none of the above

Answer 1

First, we multiply the first equation by "2":

$\begin{gathered} 2\times\lbrack5x-2y=3\rbrack \\ 10x-4y=6 \end{gathered}$

Then, we multiply the second equation by "-5":

$\begin{gathered} -5\times\lbrack2x-y=0\rbrack \\ -10x+5y=0 \end{gathered}$

The two new equations are:

$\begin{gathered} 10x-4y=6 \\ -10x+5y=0 \end{gathered}$

We add both equations and solve for y. The steps are shown below:

$\begin{gathered} 10x-4y=6 \\ -10x+5y=0 \\ ----------- \\ y=6 \end{gathered}$

The correct answer is y = 6.

AnswerB