Question

Use the vertex and intercept to sketch the graph of the quadratic function.

Answer 1

The expression we have is:

$f(x)=9-(x+3)^2$

We need to compare this expression with the Vertex form of the quadratic equation:

$f(x)=a(x-h)^2+k$

Where the vertex is at (h,k).

We rewrite our expression as follows:

$f(x)=-(x-(-3))^2+9$

And we can see that h=-3, and k=9. Thus, the vertex of this quadratic function is at:

$(-3,9)$

Also, since we have a negative sign along side the x, that means that the parabola opens down.

And the correct result is:

Option C