Respuesta :

EXPLANATION

Given the following operation:

3/4 - 1/2*7/8

First, let's solve 1/2*7/8:

Multiply fractions: a/b* c/d = (a*c)/(b*d)

[tex]=\frac{1\cdot7}{2\cdot8}[/tex]

Multiply the numbers: 1*7 = 7

[tex]=\frac{7}{2\cdot8}[/tex]

Multiply the numbers 2*8=16

[tex]=\frac{3}{4}-\frac{7}{16}[/tex]

Now, we need the Least Common Multiplier of 4, 16:

The LCM of a, b is the samllest positive number that is divisible by both a and b:

Prime factorization of 4:

4 divides by 2 ---> 4= 2*2

2 is a primer number, therefore no further factorization is possible.

Prime factorization of 16:

Multiply each factor the greatest number of times it occurs in either 4 or 16

= 2*2*2*2

Multiply the numbers: 2*2*2*2 = 16

Adjust fractions based on LCM

For 3/4: multiply the denominator and numerator by 4

[tex]\frac{3}{4}=\frac{3\cdot4}{3\cdot4}=\frac{12}{16}[/tex][tex]=\frac{12}{16}-\frac{7}{16}[/tex]

Since the denominators are equal, combine the fractions:

[tex]=\frac{12-7}{16}[/tex]

Subtract the numbers: 12-7 = 5

[tex]=\frac{5}{16}[/tex]