Question

Find the equation of a line perpendicular to y + 1 =-1/2xthat passesthrough the point (-8, 7).

Answer 1

step 1

Find out the slope of the given line

we have

y+1=-(1/2)x

The slope is m=-1/2

Remember that

If two lines are perpendicular

then

their slopes are negative reciprocal

so

The slope of the perpendicular line is

m=2

step 2

Find out the equation of the line in slope-intercept form

y=mx+b

we have

m=2

point (-8,7)

substitute and solve for b

7=2(-8)+b

7=-16+b

b=23

therefore

the equation of the line is

y=2x+23