Question

Calculate the sum of interior angles of a 6 sided polygon

Answer 1

The sum of interior angles of a polygon can be calculated using the formula below.

$\begin{gathered} S\text{ = }(n-2)\times180^0 \\ \text{Where; } \\ S\text{ = sum of interior angles of the polygon } \\ n\text{ = number of sides of the polygon} \end{gathered}$

For the given question the polygon is 6 sided, so;

$n\text{ = 6}$

Substituting the value of n into the formula, we have;

$\begin{gathered} S\text{ = (6-2)}\times180^0 \\ S\text{ = 4}\times180^0 \\ S=720^0 \end{gathered}$

Therefore, the sum of interior angles of a 6 sided polygon​ is 720 degree

$S=720^0$