Solve the operation between rationals, proceed as if they were numerical fractions:
[tex]\begin{gathered} \frac{c+2}{3}-\frac{c-4}{4} \\ \frac{4(c+2)-3(c-4)}{12} \\ \frac{4c+8-3c+12}{12} \\ \frac{c+20}{12} \end{gathered}[/tex]According to this:
The numerator is c+20
The denominator is 12