Question

E. O 58.456 S48. A bullet is fired from the ground making an angle of 20 degwith the horizontal with a speed of 1500 m/s.Calculate the maximum height reached? (1 point)A. O20831.097 mB. 3642.875 mC. O8232.474 mD. O15803.894 mE. 13428.572 m9. A bullet is fired from the ground making an angle of 20 degwith the horizontal with a speed of 1500 m/s.How far (horizontally) will it fall? (1 point)

Answer 1

The maximum height of a projectile is given by:

$h=\frac{v_0^2\sin^2\theta}{2g}$

In this case, the initial velocity is 1500 m/s, the angle is 20°; then we have:

$\begin{gathered} h=\frac{(1500^)^2(\sin20)^2}{(2)(9.8)} \\ h=13428.572 \end{gathered}$

Therefore, the maximum height is 13428.572 m