Answer:
61.56%
Explanation:
Let the first American = A
• P(A goes) = 0.62
,• P(A does not) = 0.38
Let the second American = B
• P(B goes) = 0.62
,• P(B does not) = 0.38
The probability that one or both of the people chosen does not go on vacation each year
=P(A goes and B does not) or P(A does not and B does) or P(both do not)
[tex]\begin{gathered} =P(AB^{\prime})+P(A^{\prime}B)+P(A^{\prime}B^{\prime}) \\ =(0.62\times0.38)+(0.38\times0.62)+(0.38\times0.38) \\ =0.2356+0.2356+0.1444 \\ =0.6156 \end{gathered}[/tex]Therefore, the probability that one or both of the people chosen does not go on vacation each year is 61.56%.