Question

The length of a rectangular garden is 9 feet longer than its width. If the garden's perimeter is 202 feet, what is the area of the garden in square feet?

Answer 1

We have the following rectangular garden

The perimeter is 202 feet, we can do the following equality

$2(x+9)+2x=202$

Now we solve "x"

$\begin{gathered} 2x+18+2x=202 \\ 4x=202-18 \\ x=\frac{184}{4} \\ x=46 \end{gathered}$

Now, we know the longer (l = 55) and the width (w = 46)

To find the area we use the following equation

$\begin{gathered} A_R=l\cdot w \\ A_R=55\cdot46 \\ A_R=2530 \end{gathered}$

In conclusion, the area of the garden is 2530 square feet