Question

question 1A.) 4, 8, 12B.)6, 10, 26C.) 2, 6, 22D.) 1, 2, 6

Answer 1

Answer

Option C is correct.

a₁, a₂ and a₃ = 2, 6 and 22 respectively.

Explanation

We have been told that

a₀ = 1

And any term after that is given as

$a_{i+1}=4a_i-2$

So,

a₁ = 4a₀ - 2

a₁ = 4 (1) - 2

a₁ = 4 - 2

a₁ = 2

a₂ = 4a₁ - 2

a₂ = 4 (2) - 2

a₂ = 8 - 2

a₂ = 6

a₃ = 4a₂ - 2

a₃ = 4 (6) - 2

a₃ = 24 - 2

a₃ = 22

Hope this Helps!!!