Respuesta :

For solving this exercise we need the molar mass of CuNO3 which is 125.5 g/mol

Step 1) We calculate the moles of this compound:

8.54 g CuNO3 / 125.5 g/mol = 0.0680 moles CuNO3

Step 2) We calculate the volume of the solution in L:

(Remember M is equal to mol/L)

0.0680 moles CuNO3 / 0.520 mol/L = 0.131 L

Step 3) We change L to mL:

(Remember 1L=1000mL)

0.131 L x (1000mL/1L) = 131 mL

Answer: Volume = 131 mL