Question

Problem 12a) solve for x, 3(-2x +5) = 9(x-5), x=b) x = –27, x =

Answer 1

The given equation is

$3(-2x+5)=9(x-5)$

Dividing by 3 both sides, we get

$\frac{3\mleft(-2x+5\mright)}{3}=\frac{9\mleft(x-5\mright)}{3}$

$-2x+5=3(x-5)$

Multiplying 3 and (x-5) as follows.

$-2x+5=3\times x-3\times5$

$-2x+5=3x-15$

Adding 15 on both sides, we get

$-2x+5+15=3x-15+15$

$-2x+20=3x$

Adding 2x on both sides, we get

$-2x+20+2x=3x+2x$

$20=5x$

Dividing by 5, we get

$\frac{20}{5}=\frac{5x}{5}$$4=x$

Hence the value of x is 4.