Respuesta :

As given by the question

There are given that the roots: 7 and 2/5.

Now,

Since the roots are integers, we can write the equation in the given form using a = 1.

Then,

b is the opposite of the sum of the roots

So,

[tex]\begin{gathered} b=-((7)+(\frac{2}{5})) \\ b=-(\frac{35+2}{5}) \\ b=-\frac{37}{5} \end{gathered}[/tex]

And

c is the products of the roots

So,

[tex]\begin{gathered} c=7\times\frac{2}{5} \\ c=\frac{14}{5} \end{gathered}[/tex]

Now,

The desired quadratic equation is:

[tex]\begin{gathered} ax^2+bx+c=0 \\ x^2-\frac{37}{5}x+\frac{14}{5}=0 \\ 5x^2-37x+14=0 \end{gathered}[/tex]

Hence, the correct option is A.