Question

6 points 3 The coordinates of the vertices of the triangle shown are P (2,13), Q (7,1), and R (2, 1). 14 13 12 11 10 9 8 6 5 3 2. 1 R Q 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 2 7 8 What is the length of segment PQ in units?

Answer 1

We have the following:

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

replacing:

P (2,13) = (x1,y1)

Q(7,1) = (x2,y2)

$\begin{gathered} d=\sqrt[]{(7-2)^2+(1-13)^2} \\ d=\sqrt[]{5^2+12^2} \\ d=\sqrt[]{25+144} \\ d=\sqrt[]{169} \\ d=13 \end{gathered}$

The answer is 13 units