This problem involves combination with taken n Items taken r at a time
The formula for this combination is :
[tex]nC_r=\frac{n!}{(n-r)!r!}[/tex]Where n is the total number of items
and r is the objects taken at a time
The factorial, n! denotes n x (n-1) x (n-2) x (n-3) x ... x (1)
For example :
2! = 2 x 1 = 2
3! = 3 x 2 x 1 = 6
4! = 4 x 3 x 2 x 1 = 24
Now from the given problem :
we have n = 30 numbers
r = selection of 3
Then the formula will be :
[tex]30C_3=\frac{30!}{(30-3)!\times3!}[/tex]Simplifying :
27 up to 1 will be cancelled from numerator and the denominator..
Evaluating the expression will be :
24360/6 = 4060
The answer is 4060