Question

If h(x) = 3(x2 + 1) - 6, what is the value of h(10)?

Answer 1

$\begin{gathered} h(x)=3(x^2^{}+1)-6 \\ \text{when they ask by h(10) you must substitute 10 in the place of x:} \\ h(10)=3(10^2+1)-6 \\ h(10)=3(100+1)-6 \\ h(10)=3(101)-6 \\ h(10)=303-6 \\ h(10)=297 \end{gathered}$