Step 1
N2(g) + 3 H2(g) → 2 NH3(g) (must be balanced)
The limiting reactant
Data needed:
The molar mass:
For N2) 28 g/mol
For H2) 2 g/mol
For NH3) 17 g/mol
Procedure:
28 g N2 ------ 3 x 2 g H2
7.0 g N2------- X = 1.5 g H2
According to this, for 7.0 g N2, 1.5 g H2 is needed to react, but 5.0 g is provided. Therefore, H2 is the excess, and N2 is the limiting reactant
1.5 g of H2 is reacted, so 5.0 g - 1.5 g= 3.5 g are leftover
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Step 2
The theoretical yield.
Procedure:
28 g N2 ------ 2 x 17 g NH3
7.0 g N2------ X = 8.5 g NH3
Answer: The theoretical yield of ammonia is 15 g. FALSE