Question

Determine the minimum and maximum value of the following trigonometric function.
f(x)=10sin(2/5x)+5

Answer 1

ANSWER

$\begin{gathered} Minimum=-5 \\ Maximum=15 \end{gathered}$

EXPLANATION

The trigonometric function given is:

$f(x)=10\sin (\frac{2}{5}x)+5$

The minimum value a sine function can take is -1.

This means that the minimum value of the function is:

$\begin{gathered} 10(-1)+5 \\ \Rightarrow-10+5 \\ \Rightarrow-5 \end{gathered}$

The maximum value a sine function can take is 1.

This means that the maximum value of the function is:

$\begin{gathered} 10(1)+5 \\ \Rightarrow10+5 \\ \Rightarrow15 \end{gathered}$