Given the inequality equation below:
[tex]3x+4y>4[/tex]Find the y-intercept
[tex]\begin{gathered} set\text{ x=0} \\ 3x+4y=4 \\ 3(0)+4y=4 \\ 4y=4 \\ y=\frac{4}{4}=1 \\ y-intercept\rightarrow(0,1) \end{gathered}[/tex]Find the x-intercept
[tex]\begin{gathered} set\text{ y=0} \\ 3x+4y=4 \\ 3x+4(0)=4 \\ 3x=4 \\ x=\frac{4}{3} \\ x-intercept\rightarrow(\frac{4}{3},0) \end{gathered}[/tex]Find the shaded area
[tex]\begin{gathered} set\text{ x=0, and y=0} \\ 3x+4y>4 \\ 3(0)+4(0)>4 \\ 0+0>4 \\ 0>4\rightarrow false \\ Shade\text{ the side of the line where \lparen0,0\rparen is not includedand use dot line} \end{gathered}[/tex]Hence, the graph is
