Respuesta :

Let,

T = Triangle

S = Semi Circle

R = Star

D = Diamond

Given:

a.) 4 Triangles = 2 Semi Circle + 2 Star → 4T = 2S + 2R

b.) 1 Triangle + 1 Diamond = 1.05 → 1T + 1D = 1.05

c.) 1 Star + 1 Semi Circle = 0.525 → 1R + 1S = 0.525

d.) Diamond = ?

For us to be able to determine the value of the diamond, we must be able to determine the value of the Triangle.

For us to get it, we will be using first the equation at a and c.

4T = 2S + 2R

1R + 1S = 0.525

We get,

2S + 2R = 2(1S + 1R)

2S + 2R = 2(0.525)

2S + 2R = 1.05

Let's now get the value of the triangle,

4T = 2S + 2R

4T = 1.05

T = 1.05/4

T = 0.2625 (Value per triangle)

Let's now determine the value of the DIAMOND.

1 Triangle + 1 Diamond = 1.05 → 1T + 1D = 1.05

1T + 1D = 1.05

1(0.2625) + 1D = 1.05

0.2625 + 1D = 1.05

1D = 1.05 - 0.2625

1D = D = 0.7875

ANSWER: The value of the diamond is 0.7875