Question

Amer class, Mrs. Sandoval picked up several piece of paper containing students' work from SHAVN ELLA LEVI 263.140)14) + 2(3.4)() 602.86 units 21314)(a)) 2512 unit 23.425) - 2/3 4729 RUBY KATRINA LORENZO 22 28.141815) 218.1489 663.12 units 2[3.2) 203.4)(48) + 213.)(4) 30144 units Which student found the total surface area of a cylinder with a height that was two times greater than its radius? O Ruby O Lorenzo O Ella O Levi

Answer 1

we know that

the total surface of a cylinder is equal to

$SA=2B+Ph$

where

B us the area of the circular base

P is the circumference of the circular base

h is the height of the cylinder

we have

h=2r

so

$B=\pi\cdot r^2$$P=2\pi\cdot r^{}$

substitute

$SA=2(\pi\cdot r^2)+(2\pi\cdot r)\cdot h$

substitute the value of h

$\begin{gathered} SA=2(\pi\cdot r^2)+(2\pi\cdot r)\cdot2r \\ SA=2\pi r^2+4\pi r^2 \\ SA=6\pi r^2 \end{gathered}$

therefore

the answer is Rudy

because

r=4 and h=8