Question

3.What are the coordinates of the center and the length of the radius of the circle whose equation is(x + 1)^2 + (-5)^2 = 16?

Answer 1

The general equation of circle with centre (h.k) and radius r is,

$(x-h)^2+(y-k)^2=r^2$

Simplify the equation to obtain the centre and radius of circle.

$\begin{gathered} (x+1)^2+(y-5)^2=16 \\ (x-(-1))^2+(y-5)^2=(4)^2 \end{gathered}$

So center of circle is (-1,5) and radius 4.