An object is spun around in a circle of radius 6.0m with a frequency of50 Hz.a. What is the period of its rotation?b. What is its velocity?c. What is its acceleration?

Respuesta :

From the information given,

radius = 6

frequency = 50

a) Period, T is the reciprocal of frequency. This means that

T = 1/frequency

Thus,

T = 1/50 = 0.02

Period = 0.02 s

b) The formula for calculating velocity for an object in circular motion, V is expressed as

V = 2pi x radius/T

By substituting pi = 3.14, radius = 6 and T = 0.02 into the formula,

V = 2 x 3.14 x 6/0.02

V = 1884

Velocity is 1884 rad/s

c) The formula for calculating centripetal acceleration is expressed as

A = V^2/radius

Substituting V = 1884 and radius = 6 into the formula,

A = 1884^2/6 = 591576

Acceleration = 591576 rad/s^2