Question

A triangle has sides 25 centimeters, 26 centimeters, and 32 centimeters. What is the perimeter (distance10around the edges) of the triangle in centimeters? Express your answer in mixed number form, and reduce if possible.2355

Answer 1

Given that a triangle has sides of the following dimensions

$25\frac{2}{5}cm,26\frac{9}{10}cm\text{ and 32}\frac{5}{8}cm$

The diagram of the triangle can be seen below

To find the perimeter, P, of a triangle, the formula is

$P=a+b+c_{}$

Where

$\begin{gathered} a=32\frac{5}{8}=\frac{261}{8}cm \\ b=26\frac{9}{10}=\frac{269}{10}cm\text{ and } \\ c=25\frac{2}{5}=\frac{127}{5}cm \end{gathered}$

Substitute the values to find the perimeter, P, of the triangle

$\begin{gathered} P=a+b+c_{} \\ P=\frac{261}{8}+\frac{269}{10}+\frac{127}{5}=\frac{1305+1076+1016}{40}=\frac{3397}{40}=84\frac{37}{40}cm \\ P=84\frac{37}{40}cm \end{gathered}$

Hence, the perimeter, P, of the triangle is

$84\frac{37}{40}cm$