Question

- 10x + 100y = 30-3x + 30y = 9

Answer 1

The given system is

$\mleft\{\begin{aligned}-10x+100y=30 \\ -3x+30y=9\end{aligned}\mright.$

First, we multiply the first equation by -3/10.

$\mleft\{\begin{aligned}3x-30y=-9 \\ -3x+30y=9\end{aligned}\mright.$

Then, we sum the equations

$\begin{gathered} 3x-3x+30y-30y=9-9 \\ 0x+0y=0 \\ 0=0 \end{gathered}$

According to this result, we can deduct that the system doesn't have any solutions because the lines represented by the equations are parallel.