Question

In circle P with m NPQ = 82 and NP = 3 units find area of sector NPQ. Round to the nearest hundredth.

Answer 1

The area of the circular sector is given by:

$\begin{gathered} A=\frac{r^2\theta}{2} \\ where\colon \\ r=3 \\ \theta=82^{\circ}=\frac{41}{90}\pi \\ so\colon \\ A\approx6.44_{\text{ }}units^2 \end{gathered}$