Question

Write logaa=4x in exponential form and find x to evaluate logaa for any a>0, a≠1.

Answer 1

Given:

$\log _aa=4x$

To find the exponential form of the above, all we need to do is to raise the base a to the power of 4x.

That is;

$a^{4x}=a$

To find the value of x, we need to raise the power of the right - hand side so that we can equate the exponent

That is;

$a^{4x}=a^1$

4x = 1

Divide both-side by 4

$x=\frac{1}{4}$

$\text{Log}_aa=4(\frac{1}{4})$$\text{Log}_aa=1$