As per given by the question.
There are given that a triangle.
Now,
Suppose given triangle is ABC.
Then, redraw the given triangle.
Now,
For finding the value of x, and y;
First find the value of x with the help of sine trigonometric function.
So,
[tex]\sin 35^{\circ}=\frac{AB}{AC}[/tex]Then,
Substitute the value x for AB and 22 for AC.
SO,
[tex]\begin{gathered} \sin 35^{\circ}=\frac{AB}{AC} \\ \sin 35^{\circ}=\frac{x}{22} \\ 0.57=\frac{x}{22} \\ x=0.57\times22 \\ x=12.54 \end{gathered}[/tex]Now,
For finding the value of y,
Here, use pythagoras theorem in triangle ABC.
So, from the pythagoras theorem;
[tex]AB^2+BC^2=AC^2[/tex]Then,
Substitute the value in above formula;
So,
[tex]\begin{gathered} AB^2+BC^2=AC^2 \\ x^2+y^2=(22)^2 \end{gathered}[/tex]Now, put the value 12.54 for x,
So,
[tex]\begin{gathered} x^2+y^2=(22)^2 \\ (12.54)^2+y^2=(22)^2 \\ 157.25+y^2=484 \\ y^2=484-157.25 \\ y^2=326.75 \end{gathered}[/tex]Then,
[tex]\begin{gathered} y^2=326.75 \\ y=\sqrt[]{326.75} \\ y=18.076 \end{gathered}[/tex]Hence, the value of x is 12.54 and the value of y is 18.076.