Question

create a linear equation in the slope-intercept form that contains points (2,8) and (6,-4)

Answer 1

the two points are,

A(2,8)

B (6,-4)

the equation of the line in the slope intercept form is,

$y-8=\frac{-4-8}{6-2}(x-2)$$\begin{gathered} y-8=\frac{-12}{4}(x-2) \\ y-8=-3x+6 \\ y=-3x+14 \end{gathered}$

thus, the equation of the line is

y = -3x + 14