The figure ABCD has the shape of a Rhombus with diagonals AC and BD.
To determine the area of a Rhombus you have to multiply the length of both diagonals and divide the result by 2, following the formula:
[tex]A=\frac{pq}{2}[/tex]
Where
p represents the horizontal diagonal
q represents the vertical diagonal
For the quadrilateral ABCD, the lengths of the diagonals are:
AC=6cm + 15cm =21cm
BD= 8cm + 8cm=16cm
[tex]\begin{gathered} A=\frac{AC\cdot BD}{2} \\ A=\frac{21\cdot16}{2} \\ A=\frac{336}{2} \\ A=168\operatorname{cm}^2 \end{gathered}[/tex]
The area of the figure is 168cm²
