Question

Using the digits 1 to 10 at most one time each, fill in the boxes to make the result is closest to 1

Answer 1

Answer:

Using the digits 1 to 10 at most one time each to fill the given boxes, the value that makes the expression closest to 1 is;

$\frac{(\frac{10}{5})^6}{(\frac{4}{1})^3}$

Explanation:

Given the question in the attached image.

To make sure the result of the expression is closest to 1, we must make sure the value of the denominator and the numerator of the fraction is as close as possible.

$\text{ denominator }\approx\text{ numerator}$

Picking a set of values for the numerator, we must also try to select a separate set of values for the denominator that gives a result that is almost equal to the numerator.

Using this method we can arrive at a possible solution;

$\frac{(\frac{10}{5})^6}{(\frac{4}{1})^3}$

Let us simplify this expression to confirm;

$\frac{(\frac{10}{5})^6}{(\frac{4}{1})^3}=\frac{(2)^6}{(4)^3}=\frac{64}{64}=1$

Therefore, Using the digits 1 to 10 at most one time each to fill the given boxes, the value that makes the expression closest to 1 is;

$\frac{(\frac{10}{5})^6}{(\frac{4}{1})^3}$