The factor the binomial
[tex]a^2-b^2[/tex]Find the square root of a and the square root of b, then put them as the product of the sum and difference of these square roots
[tex]\begin{gathered} \sqrt{a^2}=a \\ \sqrt{b^2}=b \\ a^2-b^2=(a+b)(a-b) \end{gathered}[/tex]We will use this rule to factor in the given expression
[tex]36x^2-49[/tex]Find the square root for each term
[tex]\begin{gathered} \sqrt{36x^2}=6x \\ \sqrt{49}=7 \end{gathered}[/tex]Write the two factors
[tex]36x^2-49=(6x+7)(6x-7)[/tex]The answer is the last choice (6x + 7)(6x - 7)
