Question

Using the Gay-Lussac LawIf I have 7.7 moles of gas at a pressure of 0.09 atm at a temperature of 56 C°, what is the volume of the container that the gas is in?

Answer 1

ANSWER

EXPLANATION

Given that;

The number of moles of the gas is 7.7 moles

The pressure of the gas is 0.09 atm

The temperature of the gas is 56 degrees Celcius

Follow the steps below to find the volume of the gas in the container

Step 1; Convert the temperature to degrees Kelvin

$\text{ T K = t}\degree C\text{ + 273.15}$$\begin{gathered} \text{ T K = 56 + 273.15} \\ \text{ T K = 329.15K} \end{gathered}$

Step 2; Apply the ideal gas equation

$\text{ PV = nRT}$$\begin{gathered} \text{ Recall, that R = 0.08205 L atm mol}^{-1}K^{-1} \\ \text{ 0.09 }\times\text{ V = 7.7 }\times\text{ 0.08205 }\times\text{ 329.15} \\ \text{ 0.09V = 207.95} \\ \text{ Divide both sides by 0.09} \\ \text{ V = }\frac{\text{ 207.95}}{\text{ 0.09}} \\ \text{ V = 2310.58 Liters} \end{gathered}$

Therefore, the volume of the container is 2310.58 liters