Question

In the triangle below, if < C = 62 °, what is the measure of angle B?

Answer 1

In the given triangle ABC

$BA=BC$

Then the triangle is isosceles

In the isosceles triangle, the base angles are equal

Since $m\angle A=m\angle C$Since m$m\angle A=62^{\circ}$In any triangle the sum of angles is 180 degrees, then

$m\angle A+m\angle B+m\angle C=180^{\circ}$

Substitute angles A and C by 62

$\begin{gathered} 62+m\angle B+62=180 \\ \\ m\angle B+124=180 \end{gathered}$

Subtract 124 from both sides

$\begin{gathered} m\angle B+124-124=180-124 \\ \\ m\angle B=56^{\circ} \end{gathered}$

The answer is b