Answer:
Explanation:
Given the results of the number of movies watched by the group of students and the frequency, we're asked to determine the mean and median for the number of movies watched per student.
We'll follow the below steps to solve for the mean and median;
1. Find the product of the number of movies and frequency;
[tex]\begin{gathered} 0\times8=0 \\ 1\times8=8 \\ 2\times5=10 \\ 3\times5=15 \\ 4\times7=28 \end{gathered}[/tex]2. Find the sum of the product of the number of movies and frequency;
[tex]0+8+10+15+28=61[/tex]3. Find the sum of the frequency;
[tex]8+8+5+5+7=33[/tex]The mean can now be determined using the below formula;
[tex]\begin{gathered} \text{Mean}=\frac{\Sigma(f\cdot x)}{\Sigma f} \\ \text{where} \\ \Sigma(f\cdot x)=\text{ sum of the product of the number of movies and frequency} \\ \Sigma f=\text{ sum of the frequency} \end{gathered}[/tex]Therefore, our mean is;
[tex]\text{Mean}=\frac{61}{33}=1.85[/tex]We can go ahead and determine the median using the below formula;
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