Respuesta :

Question:

Solution:

Let the following trigonometric equation:

[tex]2\sin (x)+\sqrt[]{3}=\text{ 0}[/tex]

Subtract the root of 3 from both sides of the equation:

[tex]2\sin (x)=-\sqrt[]{3}[/tex]

solve for sin(x):

[tex]\sin (x)=\text{ -}\frac{\sqrt[]{3}}{2}[/tex]

Applying the trigonometric circle on the given interval, we obtain that the correct answer is:

[tex]x\text{ = }\frac{4\pi}{3}\text{ , x = }\frac{5\pi}{3}[/tex]

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