Question

Find the area of the figure. Use 3.14 for .18 in9 inO A. 97.2 in2O B. 122.24 in2O C. 61.12 in2D. 86.24 in2

Answer 1

SOLUTION

We want to solve the question below

The figure consists of a semi-circle and a triangle. So the area of the figure becomes

Area of semi-circle + area of triangle

The semi-circle has a diameter of 8 in. So the radius becomes

$r=\frac{diameter}{2}=\frac{8}{2}=4in$

Area of the semi-circle is given as

$\begin{gathered} \frac{1}{2}\times\pi r^2 \\ \frac{1}{2}\times3.14\times4^2 \\ \frac{1}{2}\times3.14\times16 \\ =25.12\text{ in}^2 \end{gathered}$

Area of the triangle is

$\begin{gathered} \frac{1}{2}\times base\times height \\ \frac{1}{2}\times9\times8 \\ 9\times4 \\ =36\text{ in}^2 \end{gathered}$

So Area of the figure becomes

$\begin{gathered} 25.12+36 \\ =61.12\text{ in}^2 \end{gathered}$

Hence the answer is option C